Question

The equation 5x^2-10x+5=0 can be written in the form (px+q)^2+r=0, where p,q and r are integers. Find the value of p,q and r.

Answer 1

\[5(x-1)^2=0\]

Answer 2

how, did you equate like terms?

Answer 3

actually no. i factored out the 5 form the expression to get
\[5(x^2-2x+1)=0\] and then i recognize
\[x^2-2x+1\] as a perfect square, namely
\[x^2-2x+1=(x-1)^2\] so we get
\[5(x-1)^2=0\]

Answer 4

what are the values of p,q and r

Answer 5

p^2x^2=5x^2
so p^2=5
so p=??????

Answer 6

actually i don't think we can write this as
\[(px+q)^2+r=0\] but we can write this one
\[(x-1)^2=0\] in that form.
\[p=1, q =-1, r = 0\]

Answer 7

really?