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in triangle ABC, controid D is on median line AM. AD=x+5 and DM=3x-5. what is AM?
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Can you draw the triangle ?
uhhh..i dont know how to thank you anyway...
Wait i am drawing it i solved it i guess
|dw:1323357466442:dw| \[3k=x+5\] --> AD \[k=(x+5)/3\] \[k=3x+5\] --> DM \[3(3x-5)=x+5\] \[6x-15=x+5\] \[5x=20\] \[x=4\]
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