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subtract x/x-2 x+1 - 2/ x-1 x+1
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You should use paretheses becuase i can tell which parts are fractions
(x/(x-2)(x+1)- 2/ (x-1)(x+1)
\[=(\frac{x}{(x-2)(x+1)} \times \frac{x-1}{x-1})-( \frac{2}{(x-1)(x+1)} \times \frac{x-2}{x-2})\]
\[=\frac{x(x-1)-2(x-2)}{(x-1)(x-2)(x+1)}\]
\[=\frac{x^2-3x+4}{(x-1)(x-2)(x+1)}\]
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thanks sweetheart
:D:D
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