Question

6k-3k2)=3(k-2) step by step plz

Answer 1

I dont get it because theres no opening to the first parenthisis> )

Answer 2

is this suppose to read as 6k-3k^2=3(k-2)?

Answer 3

no

Answer 4

Okay. 6k-3(k+2)=3(k-2)
multiply -3 by each term inside the parentheses
6k-3k-6=3(k-2)
since 6k and -3k are ike terms, add -3k to 6k to get 3k
3k-6=3(k-2)
multiply 3 by each term inside the parentheses again
3k-6=3k-6
since 3k has the variable to solve for, move it to the left hand side of the equation by subtracting 3k from both sides
3k and -3k are like terms add -3k to 3k to get o
0-6=-6
remove the 0 from the polynomial; adding or subtracting 0 doesn't change the value of the expression.
-6=-6
since -6=-6, the expression will always be true.