Tickets=19, People =200.Option 1= $2.00 Admission $.50 Per ticket ,19x$.50x 200 people = $1900 ticket Profit +400$= 2300 together. Option 2= No Admission, 1.00$ per ticket ,$1.00x19x200=3800.
Profit Equal income(the money take in) minus expenses. for each option, Write an Equation to find the profit Y of selling X tickets. Assume that 200 people will attend and use $1000 as your expenses. Graph the equtions in the same Coordinate Plane. For which numbers of tickets sold are the two options equal? what is the profit or loss for this number of tickets? also what would the Formula be for

Question

Tickets=19, People =200.Option 1= $2.00 Admission $.50 Per ticket ,19x$.50x 200 people = $1900 ticket Profit +400$= 2300 together.  Option 2= No Admission, 1.00$ per ticket ,$1.00x19x200=3800.
Profit Equal income(the money take in) minus expenses. for each option, Write an Equation to find the profit Y of selling X tickets. Assume that 200 people will attend and use $1000 as your expenses.       Graph the equtions in the same Coordinate Plane. For which numbers of tickets sold are the two options equal? what is the profit or loss for this number of tickets?  also what would the Formula be for