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|x| > 1
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|x| > b x>b x<-b
what about; -3|2w| = -6
|2w| = 2 w=+-1
Which question?
no its \(w=\pm1\)
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ok
@Thomas.A so how would the inequality be solved now?
-3|2w| = -6 -3 multiplied by |2w} = -6 call |2w| x now -3x = -6 x=2 substitute back: |2w|=2 w=-1 w=1
slaibaak showed how to solve inequality
i was good at math, until they decided to add alphabet to it. -.-
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lol
haha. substitute any value into b. That's a generic answer I have. Will work with any value you want to plug in
clear cache
ctrl+f5
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Well, non-negative values
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