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Mathematics 10 Online
OpenStudy (anonymous):

|x| > 1

OpenStudy (slaaibak):

|x| > b x>b x<-b

OpenStudy (anonymous):

what about; -3|2w| = -6

OpenStudy (slaaibak):

|2w| = 2 w=+-1

OpenStudy (slaaibak):

Which question?

OpenStudy (anonymous):

no its \(w=\pm1\)

OpenStudy (lilg132):

ok

OpenStudy (anonymous):

@Thomas.A so how would the inequality be solved now?

OpenStudy (slaaibak):

-3|2w| = -6 -3 multiplied by |2w} = -6 call |2w| x now -3x = -6 x=2 substitute back: |2w|=2 w=-1 w=1

OpenStudy (anonymous):

slaibaak showed how to solve inequality

OpenStudy (anonymous):

i was good at math, until they decided to add alphabet to it. -.-

OpenStudy (anonymous):

lol

OpenStudy (slaaibak):

haha. substitute any value into b. That's a generic answer I have. Will work with any value you want to plug in

OpenStudy (lilg132):

OpenStudy (anonymous):

clear cache

OpenStudy (anonymous):

ctrl+f5

OpenStudy (slaaibak):

Well, non-negative values

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