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Mathematics 8 Online
OpenStudy (anonymous):

how many ways can you rearrange the letters in the phrase "ILOVEMATH"

OpenStudy (anonymous):

Math I love? XD

OpenStudy (anonymous):

Well since there are no repeats it's just n!, where n is the number of letters

OpenStudy (anonymous):

Like how many combonations

OpenStudy (anonymous):

I need a specific number

OpenStudy (anonymous):

Hmm...

OpenStudy (anonymous):

it's 9!

OpenStudy (anonymous):

do you know how to compute that?

OpenStudy (anonymous):

soo its 362 880

OpenStudy (saifoo.khan):

9! = 362880

OpenStudy (anonymous):

How do you compute that because im still confused.

OpenStudy (anonymous):

oh dear lord, i have no idea what that means

OpenStudy (anonymous):

x! (which you read "x factorial") is the product of all numbers from x down to 1

OpenStudy (anonymous):

oh, thats easy! I cant believe I didn't remember that. We are having an EOCT and that was on our study guide and we learned that the first month of school so i forget. Silly me c:

OpenStudy (anonymous):

1 1 2 2 3 6 4 24 5 120 6 720 7 5040 8 40320 9 362880 10 3628800

OpenStudy (anonymous):

Well if they give you duplicate letters you have to account for those.. so becareful

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