Question

how do you solve this equation? 16x^2=64 ?

Answer 1

2^4 x^2 = 2^6

x^2 = 2^2

x = 2

x = -2

Answer 2

@saifoo

it should be
\[x = \pm \sqrt{4}\]

Answer 3

Yes, it will be -2 and 2.

Answer 4

Thank you guys! if you could look at this question I would highly appreciate, too. :D 6x^2\[6x ^{2}+11x-2=0\]

Answer 5

x = -2
x = 1/6

Answer 6

would you mind showing me the work if its not too much? :)

Answer 7

6x^2 + 11x -2 = 0

6x^2 +12x - x - 2 = 0
6x(x+2) -1(x+2) = 0
(x+2)(6x-1)=0

x= -2

x = 1/6