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I have a question on this one equation that someone sovled. An isosceles triangle in which angles B and C have the same measure. Find the measure of each angle whose degree is represented with variables. A= 4x + 2y B= 9y - 2 C= 10x + 10 We know B = C,so we know 10x + 10 = 9y - 2 thus x = (9y -12)/10 and A + B + C = 180 14x + 11y + 8 = 180 14 (9y - 12)/10 + 11y = 172 126y - 168 + 110y = 1720 236y = 1888 y = 8 x = (72 - 12)/10 = 6 So B = 70 C = 70 A = 40 On this one Equation how did someone get 14 on this equation: from x = (9y -12)/10 to 14 (9y - 12)/10 + 11y = 172 equation
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9y - 2 = 10x + 10 4x + 2y + 9y - 2 + 10x + 10 = 180 x = 6 y= 8
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