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if f(x) = x^2 - 10x + 28 what is the vertex, range, and yint
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Jinnie, do you mind if I point out that you've been asking this type of questions for weeks already? ^^ To find the vertex of a quadratic function, you differentiate it, set it equal to zero, solve for x and plug this x into the original function to form the coordinates of the vertex. You can find the function's range by inspection, but remember that a quadratic formula's range will never be surjective. To find the y-intercept of a function, you set x to be equal to zero.
are you sure? i have been asking alot of questions but certainly not the same questions. I know for a fact because I write that down every question and response for notes.
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