Question

Solve using the quadratic formula
10x² + 23x + 14 = 0

Answer 1

\[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\]

Answer 2

quadratic formula is x=\[-b \pm \sqrt{b ^{2}-4ac} / 2a\]

a= 10, b= -23, c=14
plug it and solve

x=\[-23\pm \sqrt{23^{2}-4(10)(14)}/2(10)\]

Answer 3

Thanks

Answer 4

you'll get an immaginary root