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Evaluate log6 14. 1.47 0.43 0.68 2.33
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This can be evaluated two ways: 1) \[\log_6(14) = {\log_{10}(14) \over \log_{10}(6)}\]2)\[\log_6(14) = {\ln(14) \over \ln(6)}\]
is it 1.47?
I got 1.25..but 1.47 is the closest
You should have gotten 1.47.
oh ok
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