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Mass m is thrown horizontally in velocity v from the top of a tower (at height h). while the mass is moving, the air resistance force is equal to f=-bv (b is a constant). find the function of the position of the mass with respect to time
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How about:\[y=y_0 +v_yt+\frac{1}{2}g t^2+f \rightarrow \sqrt{\frac{2(y-y_0-f)}{g}}=t\]
what ? how did you add the force to that equation ? i think it should be solved with differential equation of v ...
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