Question

Find the exact functional value for sin^-1 (sin(5pi/4))
Explain why the answer isn't 5pi/4

So far i have the answer i believe,
sin^-1=-sqrt2/2
-pi/2 and pi/2, please check and explain why its not 5pi/4

Answer 1

it is not
\[\frac{5\pi}{4}\] because the range of
\[\sin^{-1}\] is
\[[-\frac{\pi}{2},\frac{\pi}{2}]\]

Answer 2

thank you, I was just stuck for that little bit, I appreciate the help.

Answer 3

\[\sin(-\frac{\pi}{4})=-\frac{\sqrt{2}}{2}\] so that is -the right answer,
\[-\frac{\pi}{4}\]