Question

Find four consecutive integers such that the sum of the second and the fourth is 132.

Answer 1

Let the numbers be x, x+1, x+2, x+3
therefore x+1+x+3=132
=>2x+4=132
=>2x=128
=>x=64

Answer 2

So the numbers are 64, 65, 66, 67

Answer 3

let the integer=x
second = (x+1)
fourth= (x+3)
(x+1)+(x+3)=132
2x=132-4
2x=128
x=64

so the integers are
64,65,66,67

Answer 4

hey lalaly!

Answer 5

hey hannah:D:D