Question

Find four consecutive integers such that the sum of the second and the fourth is 132.

Answer 1

64 65 66 67
i think i've answered this before

Answer 2

This is a strange way of asking the question. Anyway, let's assume the first of the four is \(x\), then \(x+1+x+3=132 \implies 2x=128 \implies x=64\). Thus the numbers are \(64,65, 66\) and \(67\).