Question

Subract.

Answer 1

-

Answer 2

\[\left(\begin{matrix}6x_2y \\ x^2+5xy-6y^2\end{matrix}\right)-\left(\begin{matrix}3x+2y \\ x^2+4xy-5y^2\end{matrix}\right)\]

Answer 3

do you know how to add and subtract vectors?

\[\left(\begin{matrix}a \\ b\end{matrix}\right) + \left(\begin{matrix}c \\ d\end{matrix}\right) = \left(\begin{matrix}a+c \\ b+d\end{matrix}\right)\]

Answer 4

No i do not?

Answer 5

He literally told you how to up there.

Answer 6

your a = 6x2y

your c = 3x + 2y

...

does this help at all?

Answer 7

Yes now i get it... and my bad across :/

Answer 8

I got it wrong i must have misplaced something...

Answer 9

i bet you forgot to distribute the - sign

Answer 10

\[\left(\begin{matrix}6x2y - (3x+2y) \\ x^2+5xy-6y^2 - (x^2+4xy-5y^2)\end{matrix}\right)\]

Answer 11

i think that is what i forgot...