Question

Solve by factoring y^2 + 2y = 8

Answer 1

\[(y+4)(y-2)=0\]y = -4, y =2

Answer 2

can you show me how you got that?

Answer 3

Sure.

y^2 + 2y = 8
y^2 + 2y - 8 = 0
y^2 +4y -2y -8 = 0
y(y+4)-2(y+4) = 0
(y+4)(y-2) =0

And finally,
y = -4,2

Answer 4

thanks!

Answer 5

no problem.