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x^2 - 2/5x + 1/25
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It's a perfect square trinomial. Please note that 1/25 = (1/5)^2
x^2 - 2/5x + 1/25 =0, mult by 25 25x^2 - 10x + 1=0, (5x-1)(5x-1)=0 (5x-1)^2 =0 5x-1=0 x=1/5 double
Just use completing the square, \[x ^{2}+1/25-2/5x\] This is same as: \[a ^{2}-2ab+b ^{2}\] So, the equation becomes: \[(x-1/5)^{2}\] Or the final answer is: \[(x-1/5)(x-1/5)\]
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