Question

evaluaten limits

Answer 1

\[\lim_{x \rightarrow 1} x ^{3}-1/x ^{2}-1\]

Answer 2

apply lhopitals rule

Answer 3

\[\lim_{x \rightarrow 1} \frac{3x^2}{2x} = \frac{3}{2}\]

Answer 4

limx→1(x3−1/x2−1)
limx→1((x-1)(x^2+x+1))/(x-1)(x+1)
limx→1(x^2+x+1)/(x+1)
3/2 is the answer after applying limits check the formula for x3−1i have doubt in it