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Mathematics 8 Online
OpenStudy (anonymous):

limx→1x5−1/x3−1

OpenStudy (anonymous):

do you know l'hospitals rule?? or wanted to it by def?

OpenStudy (anonymous):

no.

OpenStudy (anonymous):

evaluate the limits.

OpenStudy (anonymous):

ok then simply do as follows \[\frac{x^5-1}{x^3-1}\]

OpenStudy (anonymous):

=

OpenStudy (anonymous):

\[\frac{(x-1)(x4+x3+x2+x+1)}{(x-1)(x2+x+1)}\]

OpenStudy (anonymous):

cancel x-1 throughout and then put 1 to get 5/3

OpenStudy (anonymous):

yes answer is right.

OpenStudy (anonymous):

don't forget to write lim \[\lim_{x \rightarrow 1}\]

OpenStudy (anonymous):

with each step

OpenStudy (anonymous):

i have some more questions of limits.

OpenStudy (anonymous):

no secondyear.

OpenStudy (anonymous):

oh yes and doing chapter no 1 may be exercise 1.2 etc

OpenStudy (anonymous):

what is i'hospitals rule.

OpenStudy (anonymous):

yes ex 1.2

OpenStudy (anonymous):

L'HOSPITAL RULE READ AS LAPITA RULE THIS IS NOT FOR SECOND YEAR STUDENTS YOU WILL READ IT IN BSC

OpenStudy (anonymous):

civil engineering book part2

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