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limx→1x5−1/x3−1
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do you know l'hospitals rule?? or wanted to it by def?
no.
evaluate the limits.
ok then simply do as follows \[\frac{x^5-1}{x^3-1}\]
=
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\[\frac{(x-1)(x4+x3+x2+x+1)}{(x-1)(x2+x+1)}\]
cancel x-1 throughout and then put 1 to get 5/3
yes answer is right.
don't forget to write lim \[\lim_{x \rightarrow 1}\]
with each step
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i have some more questions of limits.
no secondyear.
oh yes and doing chapter no 1 may be exercise 1.2 etc
what is i'hospitals rule.
yes ex 1.2
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L'HOSPITAL RULE READ AS LAPITA RULE THIS IS NOT FOR SECOND YEAR STUDENTS YOU WILL READ IT IN BSC
civil engineering book part2
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