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if h(x)=2g(x)-(1/(g(x)), g(0)=2 and g'(0)=-1, find the exact value of h'(0). PLEASE HELP AND SHOW ALL STEPS!
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find h'(x) \[h'(x)=2g'(x)-\frac{-1}{[g(x)]^2}g'(x) =>h'(0)=2g'(0)-\frac{-1}{[g(0)]^2}g'(0)\]
now g'(0) and g(0) are given just plug them in
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