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Mathematics 19 Online
OpenStudy (anonymous):

Factor completely 3x4 – 6x3 + 12x2 Answer 3x2(x – 2)(x – 2) 3(x4 – 2x3 + 4 x2) x2(3x2 – 6x + 12) 3x2(x2 – 2x + 4)

OpenStudy (anonymous):

\[3x^4-6x^3+12x^2\] What's common in this expression? They all have xs, so they're common at least. Each of the coefficients are also divisible by 3!

jhonyy9 (jhonyy9):

=3x2(x2 -2x +4)

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