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solve for x: 1+32/(x-2)(x+2)=8/x-2
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so the common denominator is x2 -4
yes
Hi there. Do you want to learn how to solve this or just get an answer?
solve
6
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than 1 multiply by (x2 -4) 32 multiply by nothing 8 multiply by (x+2)
if you want to get rid of the fractions,multiply the whole equation by (x-2)(x+2)
than x2 -4 +32 = 8(x+2)
x2 -4 +32=8x+16 x2 -8x +12=0
x_1,_2=(8+/- sqrt(64-48))/2 =(8+/- 4)/2 = 2 and 6
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ok ?
do you know what the excluded values that make these expressions undefined are?
2 is not a valid solution because then the divisor is undefined
yes right x not can being never 2 or -2
so the only solution is x=6
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thank you ktklown
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