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Solve. 3x2 + 12x = 3
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Do you intend the following?\[3x2+12x=3\]...or in other words...\[6x+12x=3\]
Divide by 3 first.
x^2+4x-1=0
Or \[3x^2+12x=3\]?
you can use quadratic equation, or factor. 3x2 + 12x -3 = 0 ==> x2 + 4x -1 = 0 since there is no easy factoring method, u should use the quadratic equation.
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where it is in the form ax2 + bx + c = 0 and the 2 x values = \[(-b \pm \sqrt{b^{2}- 4ac})/2a\]
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