Question

y(y +1 ) = 12

Answer 1

You can use the distributive property on the left half.
Then, use some simple algebra to simplify (XD) the equation and get it to y=

Answer 2

y(y+1)=12
y^2+y-12=0
here the coefficient of y is 1
to solve this we have to find factors of 12 which have a differnce of 1
6 and 2 ,the diff is 4
4 and 3 , diffference is 1
writing y as 4y-3y
so
y^2+4y-3y-12=0
y(y+4)-3(y+4)=0
(y+4)(y-3)=0
y+4=0
y-3=0
so y=-4 and 3

Answer 3

If you make a guess, 3*4 = 12
y = 3 for whole number value
Otherwise y(y+1)=12
y^2+y=12
y^2+y-12=0
y^2+4y-3y-12=0
y(y+4) -3(y+4)=0
(y+4)(y-3)=0
y = -4 or y = 3