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(x+1)^2 = 16
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thats not a answer...
We have to square both sides
3
should be pm 4
3 and - 5
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(a+b)^2=a^2+2ab+b^2
You don't have to expand it. square root both sides
(x+1) should be either 4 or -4
it's easier for him to expand
but he will just copy answer
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x^2+2x+1=16 x^2+2x-15=0 x^2+5x-3x-15=0 Factor it..
\[(x+1)^2 = 16\]\[x^2+2x+1=16\]\[x^2+2x-15=0\]\[(x+5)(x-3)=0\]\[x=-5\]or\[3\]
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