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Mathematics 16 Online
OpenStudy (anonymous):

(x+1)^2 = 16

OpenStudy (anonymous):

thats not a answer...

OpenStudy (anonymous):

We have to square both sides

OpenStudy (anonymous):

3

OpenStudy (anonymous):

should be pm 4

OpenStudy (anonymous):

3 and - 5

OpenStudy (anonymous):

(a+b)^2=a^2+2ab+b^2

OpenStudy (anonymous):

You don't have to expand it. square root both sides

OpenStudy (anonymous):

(x+1) should be either 4 or -4

OpenStudy (anonymous):

it's easier for him to expand

OpenStudy (anonymous):

but he will just copy answer

OpenStudy (anonymous):

x^2+2x+1=16 x^2+2x-15=0 x^2+5x-3x-15=0 Factor it..

OpenStudy (anonymous):

\[(x+1)^2 = 16\]\[x^2+2x+1=16\]\[x^2+2x-15=0\]\[(x+5)(x-3)=0\]\[x=-5\]or\[3\]

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