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Mathematics 19 Online
OpenStudy (anonymous):

y (y+1) = 2

OpenStudy (anonymous):

\[y(y+1)=2\]\[y^2 +y-2=0\]\[(y+2)(y-1)=0\]\[y=-2\]or\[y=1\]

OpenStudy (anonymous):

I'm pretty sure of my answers... How did you get y=1 or 2?

OpenStudy (anonymous):

I mean 1

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