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find volume of the region. set up integral in this order: dzdxdy
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what are the functions
what should the limits be for dx? would it be 0~1? no function
i attached the problem^^^
are you equations right?
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the drawing is given. surface cutting plane: x+z=1, bounded by x=y^2
and x=1
given or you figures out?
given
can you see the attachment?
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barely,too small
x should go from y^2 to 1
the only part i needed to solve are the limits and then find the volume. the instructor noted that the middle integral is wrong.
ok so 0~1 would be wrong?
\[\int_{-1}^1 \int_{y^2}^1 \int_0^{1-x} dz dx dy\]
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can you explain why 0~1 is wrong?
0~1 for what?
instead of y^2~1
|dw:1323640914109:dw| x from 0~ 1 would get you rectangle
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