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Mathematics 22 Online
OpenStudy (anonymous):

Numbers 1 - 10 are written on cards and placed in a bag. Find the probability of choosing a number greater than 5 or choosing an odd number.

OpenStudy (pokemon23):

5/10 =odd number

OpenStudy (pokemon23):

1,3,5,7,9 =odd numbers

OpenStudy (zarkon):

isn't it 5/10 for greater than 5

OpenStudy (pokemon23):

and I think I am wrong :'( I think so too

OpenStudy (pokemon23):

5/10=greater than 5

OpenStudy (zarkon):

P(number greater than 5 or choosing an odd number) =P(number greater than 5)+P(choosing an odd number)-P(number greater than 5 and choosing an odd number)

OpenStudy (zarkon):

or you can just count all the possibilities

OpenStudy (zarkon):

{1,3,5,7,9} {6,7,8,9,10} the union of these two sets is {1,3,5,6,7,8,9,10} there are 8 numbers here out of the 10 possible

OpenStudy (anonymous):

correct. . . . 4/5

OpenStudy (anonymous):

8/10 or 4/5

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