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Mathematics 13 Online
OpenStudy (anonymous):

factor completely 8x^2+18x+9

OpenStudy (anonymous):

8x^2+18x+9 (4x+3)(2x+3)

myininaya (myininaya):

\[a=8;b=18;c=9 => a \cdot c=(8)(9)=(4)(18)=(12)(6)\] \[8x^2+12x+6x+9\] now factor by grouping \[4x(2x+3)+3(2x+3)=(2x+3)(4x+3)\]

OpenStudy (anonymous):

so (2x+3)(4x+3) is the answer

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