Question

Evaluate the polynomial
x^2yz+x+y, when x=2, y=-3, and z=2

Answer 1

\[(2)^2(-3)(2)+2+(-3)\]
what does order of operations tell us to do first?

Answer 2

-25

Answer 3

parenthesis

Answer 4

then exponents

Answer 5

so we would have
\[4(-3)(2)+2+(-3)\]

Answer 6

the multiplication and division as it occurs left to right
-12(2)+2+(-3)
-24+2+(-3)

Answer 7

ok then add n sub

Answer 8

then addition and subtraction as it occurs left to right
-22+(-3)
-25

Answer 9

X^2yz+x+y, when x =2, y=-3, and z = 2
substitute the given values
{(2)^2} (-3)(2)+(2)+(-3)
perform the indicated operations
(4)(-6)+2-3
-24+2-3
-27+2
-25 (ans)

Answer 10

-25