Question

try

Answer 1

\[\left[ 2/b ^{-2} \right]^{3}\]

Answer 2

\[\frac{2^3}{b^{-2 \cdot 3}}\]
hope this helps

Answer 3

remember \[2^3=2(2)(2)=8\]
and
\[\frac{1}{b^{-2 \cdot 3}}=\frac{1}{b^{-6}}=b^6\]

Answer 4

so 8 over b^6?

Answer 5

yes

Answer 6

wait no
8 times b^6