Question

A stone is thrown vertically upwards with initial velocity u.Find the distance travelled by it in time 1.5u/g

Answer 1

i got 3u^2/8g but answer given is 5u^2/8g

Answer 2

s=ut+1/2at^2
u=u
a=-g
t=1.5u/g
s=u*1.5u/g-1/2*g*2.25*u^2/g^2
s=1.5u^2/g-2.25u^2/2g
s=0.75u^2/2g
s=0.375u^2.g
s=3u^2/8g

Answer 3

When s=u*1.5u/g-1/2*g*2.25*u^2/g^2 what happened to the -1/2*g*2.25*u^2/g^2 to get -2.25u^2/2g ?