Question

Solve
6x^2-5x+1=0

Answer 1

6x^2-5x+1=0
standard equation is
ax^2+bx+c=0
first see the product of a and b here it is 6
find factors of 6 which have a difference or sum of 5
-3 and -2 , sum is -5 product is 6
6x^2-5x+1=0
6x^2-3x-2x+1=0
3x(2x-1)-1(2x-1)=0
(3x-1)(2x-1)=0
x=1/3 and 1/2

Answer 2

+ means we add,
- means they are both -

*6 means we /6 later

(x- /6) (x- /6)

6*1 = 6

3*2 = 6; 3+2 = 5


(x- 3/6) (x- 2/6)

(x- 1/2) (x- 1/3)

(2x- 1) (3x- 1)

Answer 3

lol ... i factored instead :)

yeah, x=1/2 or 1/3

Answer 4

thanks