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OpenStudy (anonymous):
PLEASE HEP! A simplified version of the expression 2sinθ (cos θ)(cotθ) is ? sin^2 θ cos^2 θ 2sinθ (cscθ) 2cos^2 θ
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OpenStudy (anonymous):
2cos^2 θ
OpenStudy (anonymous):
Are you sure?
OpenStudy (anonymous):
cot is cos/sin
OpenStudy (anonymous):
so it can be written as 2sincos^2 / sin
OpenStudy (ash2326):
2 sin theta cos theta*cot theta co=cos/sin 2 sin theta*cos theta*cos theta /sin theta we get 2 cos^2 theta
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OpenStudy (anonymous):
which then simplifies to 2cos^2
OpenStudy (anonymous):
O thanks !
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