Mathematics
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OpenStudy (anonymous):
how to tell if vector is unit vector
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OpenStudy (anonymous):
it has something to do with taking the magnitude of the vector, but that is all i remember
OpenStudy (anonymous):
unit vector has a length of 1... thus you should use pythagoras to check
OpenStudy (amistre64):
how long is it?
OpenStudy (anonymous):
and it starts from the origin, ofc.
OpenStudy (anonymous):
i just mean in general
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OpenStudy (anonymous):
square each component , add them
OpenStudy (anonymous):
should be 1 if it is unit vector
OpenStudy (amistre64):
\[\sqrt{(x_0)^2+(x_1)^2+(x_2)^2+(x_3)^2+...+(x_n)^2}=1\]
OpenStudy (anonymous):
okay, so if the magnitude is 1, then it is a unit vector?
OpenStudy (anonymous):
<3/5,4/5>
square them
9/25 + 16/25= 25/25=1
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OpenStudy (amistre64):
i spose the sqrt part is redundant lol
OpenStudy (anonymous):
true
OpenStudy (anonymous):
someone is studying hard for Calc III
OpenStudy (anonymous):
ok, so if not unit vector, then to make unit vector divide by magnitude?
OpenStudy (anonymous):
yep
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OpenStudy (amistre64):
yep: v/|v| = unit
OpenStudy (anonymous):
lol, yeah, i have a final exam Thursday
OpenStudy (anonymous):
<2,4>
2^2+ 4^4 =20
magnitude Sqrt[20]
1/sqrt[20]<2,4>
OpenStudy (anonymous):
great! thanks guys! this is stuff from beginning of semester. :D
OpenStudy (anonymous):
* Correction
2^2 +4^2=20
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OpenStudy (anonymous):
Imranmeah91, can you help me with my question once you are done here?? Thank you (:
OpenStudy (anonymous):
so you get double/triple, line , green, stokes,?