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Mathematics 20 Online
OpenStudy (anonymous):

how to tell if vector is unit vector

OpenStudy (anonymous):

it has something to do with taking the magnitude of the vector, but that is all i remember

OpenStudy (anonymous):

unit vector has a length of 1... thus you should use pythagoras to check

OpenStudy (amistre64):

how long is it?

OpenStudy (anonymous):

and it starts from the origin, ofc.

OpenStudy (anonymous):

i just mean in general

OpenStudy (anonymous):

square each component , add them

OpenStudy (anonymous):

should be 1 if it is unit vector

OpenStudy (amistre64):

\[\sqrt{(x_0)^2+(x_1)^2+(x_2)^2+(x_3)^2+...+(x_n)^2}=1\]

OpenStudy (anonymous):

okay, so if the magnitude is 1, then it is a unit vector?

OpenStudy (anonymous):

<3/5,4/5> square them 9/25 + 16/25= 25/25=1

OpenStudy (amistre64):

i spose the sqrt part is redundant lol

OpenStudy (anonymous):

true

OpenStudy (anonymous):

someone is studying hard for Calc III

OpenStudy (anonymous):

ok, so if not unit vector, then to make unit vector divide by magnitude?

OpenStudy (anonymous):

yep

OpenStudy (amistre64):

yep: v/|v| = unit

OpenStudy (anonymous):

lol, yeah, i have a final exam Thursday

OpenStudy (anonymous):

<2,4> 2^2+ 4^4 =20 magnitude Sqrt[20] 1/sqrt[20]<2,4>

OpenStudy (anonymous):

great! thanks guys! this is stuff from beginning of semester. :D

OpenStudy (anonymous):

* Correction 2^2 +4^2=20

OpenStudy (anonymous):

Imranmeah91, can you help me with my question once you are done here?? Thank you (:

OpenStudy (anonymous):

so you get double/triple, line , green, stokes,?

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