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Simplify (7/(w+3))+((w+7)/(w^2-9))+(6/(w-3))
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\[\frac{7}{w+3}+\frac{w+7}{w^2-9}+\frac{6}{w-3}\]
\[\frac{7}{w+3}+\frac{w+7}{(w+3)(w-3)}+\frac{6}{w-3}\]
Is that as far as you can go?
\[\frac{7(w-3)+(w+7)+6(w+3)}{(w+3)(w-3)}\]
alright that's what i thought. i wasn't sure if i could make any more simplifications
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