Question

find the exact values of the six trigonometric functions of t.
(-1/5, 2 sqrt 6/5)

Answer 1

this is a point on the unit circle since
\[(\frac{1}{5})^2+(\frac{2\sqrt{6}}{5})^2=1\]

Answer 2

so you can read them off
sine is the second coordinate
cosine is the first
tangent is second over first
cosecant is the reciprocal of the second
secant is the reciprocal of the first
cotangent is the reciprocal of tangent or first over second

Answer 3

I'm a little confused still....would you mind explaining again?