Question

find the positve value of k for which the given equation as real and equal roots 4x^2-3kx+1=0

Answer 1

for equal root the determinant D=0
ax^2+bx+c=0
D=b^2-4ac
here equation is
4x^2-3kx+1=0
a=4
b=-3k
c=1
D=9k^2-4*4*1
D=9k^2-16
D=0 for equal roots
9k^2-16=0
k^2=16/9
k=4/3 or -4/3