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Why is ((y-2x)/(2y-x)) equal to ((2x-y)/(x-2y))?
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\[(y-2x)\div(2y-x)=(2x-y)\div(x-2y)\] cross multiply it....this is what you get \[(y-2x)(x-2y)=(2x-y)(2y-x)\] and then solve it
just ((y-2x)/(2y-x)) multiply by minus
sry just mutiply ((y-2x)/(2y-x)) by minus
xD 3 years ago
simply ((y-2x)/(2y-x)) = (-(2x-y)/-(x-2y)) = (2x-y)/(x-2y)
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got it :D
Hey get out of here! This is my past we're talking about hahaha
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