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Mathematics 21 Online
OpenStudy (anonymous):

(n^2-n-4)(5n-1) please show steps to solve. thx

OpenStudy (matt101):

If the point here is to expand and simplify, you have to multiply each term of the first factor by each term of the second factor: (n^2-n-4)(5n-1) = 5n^3 - n^2 - 5n^2 + n - 20n + 4 = 5n^3 - 6n^2 - 19n + 4

OpenStudy (anonymous):

Are you looking to learn the method or just get an answer? If you just want an answer you can go to wolfram alpha

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