Question

What is the 32nd term of the arithmetic sequence where a1 = –32 and a9 = –120?

Answer 1

Difference between terms is 11. So, the series is:
a(n) = -32-(11*(n-1))

a(32) = -32-11*31 = -373

Answer 2

thank you so much for your help (:

Answer 3

Medal?

Answer 4

im new to this, so im kind of lost on what that means lol