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Mathematics 9 Online
OpenStudy (anonymous):

factoring by grouping 12a^3-9a+4a-3

OpenStudy (anonymous):

It's prime

OpenStudy (anonymous):

When u factor it you get 3a(4a^2 - 3) (4a-3)

OpenStudy (anonymous):

\[12a ^{3}-9a+4a-3\] \[12a ^{3}+4a-9a-3\] \[4a \left( 3a+1 \right)-3\left( 3a+1 \right)\]

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