Question

If 4^x-4^x-1=24, what is the value of (2x)^x?

Answer 1

let me rewrite it: 4^x-4^(x-1)=24

Answer 2

can't get the answer D:

Answer 3

4^x(1-4^-1)24
4^x(1-1/4)=24
4^x=24*4/3
4^x=32
taking log 2 on both sides
log 4^x=log 32 . log is log to the base 2
xlog4=log32
x*2=5
x=2.5 or 5/2
we have to find (2x)^x
(2*5./2)^(5/2)
(5)^5/2
or root (5^5)
or 25root(5)

Answer 4

Thank you so much :D