Question

anyone willing me to tutor me for my test tomorrow?

Answer 1

Math exam consist of these topics Motion problems:R*T=D
Multiply monomial
Divide monomials
Negative and zero exponents
: defining a polynomial by number
of temrs and degree when in standard from

Answer 2

Just for today :)

Answer 3

soooooo?

Answer 4

can you help me?

Answer 5

It's really best just to ask the questions, I don't know how many of them I can stick around for.
Whaddya got?

Answer 6

well simply I don't have a question I just want to see what I need to work on.?

Answer 7

by someone writing me questions

Answer 8

not really sure what you need

can you simplify\[(-2x)^{-3}\]that's a start...

Answer 9

ok

Answer 10

1/(-2x)^3=-1/8x^3

Answer 11

I kind of struggle

Answer 12

assuming you mean-1/(8x^3) you're correct
be sure to use parentheses

Answer 13

you meant \[{-1\over8x^3}\]right?

Answer 14

yes

Answer 15

good, then you have no problem there

Answer 16

kind of have?

Answer 17

like how? you got the correct answer.
how about simplifying\[(3x^3)(2x)^{-4}\]?

Answer 18

ok let me

Answer 19

3x*2x=6x

Answer 20

1/6x^1

Answer 21

not quite, first simplify \[(2x)^{-4}\]you cant multiply what is inside the parentheses until you have gotten rid of the exponents outside of them

Answer 22

1/2x^4

Answer 23

right?

Answer 24

no, you forgot this rule:\[(ab)^x=a^xb^x\]you neglected the 2, try again...

Answer 25

x^4

Answer 26

no watch:\[(2x)^{-4}={1\over(2x)^4}={1\over2^4x^4}={1\over16x^4}\]follow that?

Answer 27

we applied two rules above:\[(ab)^x=a^xb^x\]and\[x^{-a}={1\over x^a}\]