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myininaya (myininaya):
really?
OpenStudy (anonymous):
there are harder ones coming after this one
myininaya (myininaya):
lol
OpenStudy (anonymous):
I just want to do a sanity check before I tackle the other ones
myininaya (myininaya):
you know what you should do?
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OpenStudy (anonymous):
abs(x-3) = x-3 if x-3 > 0 else -(x-3)
myininaya (myininaya):
you should ask them to solve both of these
|x-3| <-8
and |x-3|=-8
OpenStudy (anonymous):
x-3 = 8
x= 11
and
-(x-3) = 8
-x+3 = 8
x = -5
myininaya (myininaya):
i bet you a lot of them would get it wrong
OpenStudy (anonymous):
lol that is the very next question
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myininaya (myininaya):
i don't know how many times i have told me on here |something| does not have negative output so |f(x)|=-8 has no solution
|f(x)|>0 is never less than 0
OpenStudy (anonymous):
so x-3 = 8 or x-3 = -8
so -5 <= x <= 11 is that right?
OpenStudy (anonymous):
lol I'm wrong
myininaya (myininaya):
or you still talking about the equation you gave?
OpenStudy (anonymous):
yes
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myininaya (myininaya):
that one guy has it right
OpenStudy (anonymous):
yeah :-D
myininaya (myininaya):
did you mean for it to be an inequality?
OpenStudy (anonymous):
no he's right
myininaya (myininaya):
ok
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