Question

Someone help me graph this function g(x)=x^2-3

Answer 1

its basically the graph of x^2...then just shift it down by 3 units on the y-axis...in this case the vertex that was originally at (0,0) will now be at (0,-3)

Answer 2

So what would be a point for the x axis?

Answer 3

do you mean the roots...if so, those are

\[\pm3\]

Answer 4

Well cause its asking me for direct points on the graph. So I got the vertex now I just need the other lovely numbers

Answer 5

well...i guess you could say (-3,0) and (3,0) which again, are basically just the roots