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Mathematics 21 Online
OpenStudy (anonymous):

What is the max value? It occurs at X= f(x)-3x^2+30x-6

OpenStudy (anonymous):

\[f(x) = 3x ^{2} + 30x -6\] dy/dx = 6x + 30 6x = -30 x = -5

OpenStudy (anonymous):

substituting -5 back will give you -81 so max value is x=-5 and y=-81

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