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OpenStudy (anonymous):
What is the max value? It occurs at X= f(x)-3x^2+30x-6
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OpenStudy (anonymous):
\[f(x) = 3x ^{2} + 30x -6\] dy/dx = 6x + 30 6x = -30 x = -5
OpenStudy (anonymous):
substituting -5 back will give you -81 so max value is x=-5 and y=-81
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