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how do you solve 10A^5 B^2 C^9/6A B^5 C?
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\[\frac{10A^5 B^2 C^9}{6A B^5 C}\] \[\frac{5A^4C^8}{4B^4}\]
"solve" means "find the value of a given variable in terms of the others." So like, "solve 2x + 1 = 5" makes sense... x = 2. Your question is asking you to "simplify". :) It's an important difference.
sorry i meant simplify
No prob. :)
how would you simplify it?
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Scroll down to the table: http://www.mathsisfun.com/algebra/exponent-laws.html Those are the exponent rules. Here are LOTS of examples: http://tutorial.math.lamar.edu/Classes/Alg/RealExponents.aspx :)
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